Revision as of 13:30, 18 June 2009

CyPhyNets: Laboratory for Cyber Physical Networks and Systems.

$a x 2 + b x + c = 0$

$α 2 + β 2 = 1$

Addition: $(a + b i) + (c + d i) = (a + c) + (b + d) i$
Subtraction: $(a + b i) - (c + d i) = (a - c) + (b - d) i$
Multiplication: $(a + b i)(c + d i) = a c + b c i + a d i + b d i 2 = (a c - b d) + (b c + a d) i$
Division: $\,\frac{a + bi}{c + di} = \left({ac + bd \over c^2 + d^2}\right) + \left( {bc - ad \over c^2 + d^2} \right)i\,,$
Division: Failed to parse (Cannot write to or create math temp directory): \over{a + bi}{c + di}

School of Science & Engineering, SSE

Lahore University of Management Sciences LUMS

Lahore, Pakistan

Group Members

Positions open.

Shahzad Bhatti, Lecturer in Mathematics, COMSATS Institute of Technology, Islamabad

Complex networked systems to enable the deployment of very-large scale uniquitous instances of sensor networks, robotic swarms and mobile networking
Rapid information discovery in massive high-dimensional data sets in robotics, networks and other areas using geometrical and topological methods
Quantum information theory and quantum control for understanding the physics of information

@@ Line 5: / Line 5: @@
 <math>\alpha^2+\beta^2=1</math>
+[[Image:f/c/6/fc6366dd1fd484528b085dff42ba1027.png]]
 :* Addition: <math>(a + bi) + (c + di) = (a + c) + (b + d)i</math>
@@ Line 10: / Line 11: @@
 :* Multiplication: <math>(a + bi) (c + di) = ac + bci + adi + bd i^2 = (ac - bd) + (bc + ad)i</math>
 :* Division: <math>\,\frac{a + bi}{c + di} = \left({ac + bd \over c^2 + d^2}\right) + \left( {bc - ad \over c^2 + d^2} \right)i\,,</math>
-:* Division: <math>\,\frac{a + bi}{c + di} = </math>
+:* Division: <math>\over{a + bi}{c + di}</math>
 School of Science & Engineering, [http://sse.lums.edu.pk SSE]